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Chemistry · Unit 14

Chemistry of Hydrocarbons: MDCAT Notes and MCQs

Alkanes (CnH2n+2)

  • IUPAC: longest chain → number from end nearest the branch → name substituents alphabetically with locants (e.g. 2-methylbutane, 2,2-dimethylpropane).
  • sp3, tetrahedral, C–C 1.54 Å. Unreactive ("paraffins"); undergo free-radical substitution in UV light.

Free-radical chlorination of methane

  1. Initiation: Cl2 → 2Cl• (homolytic fission by UV/sunlight).
  2. Propagation: Cl• + CH4 → HCl + •CH3; •CH3 + Cl2 → CH3Cl + Cl• (chain continues).
  3. Termination: radicals combine — Cl• + Cl• → Cl2; •CH3 + •CH3 → C2H6; •CH3 + Cl• → CH3Cl.

Excess Cl2 gives CH2Cl2, CHCl3, CCl4. Ethane similarly gives C2H5Cl.

Alkenes (CnH2n)

  • IUPAC: suffix -ene; longest chain containing C=C; lowest locant to double bond (but-2-ene).
  • Ethene: each C is sp2; planar, bond angles ≈ 120°; C=C = 1 σ (sp2–sp2) + 1 π (sideways 2p–2p, above and below plane); C=C 1.34 Å. The exposed π electrons make alkenes reactive towards electrophilic addition (H2, X2, HX — Markovnikov's rule, H2O, KMnO4 → glycol (Baeyer's test, pink colour discharged), ozonolysis, polymerization).
  • Bromine water decolourised → test for unsaturation.
  • Preparation: dehydration of ethanol with conc. H2SO4 at 170 °C (or Al2O3 at 350 °C); dehydrohalogenation of ethyl halide with alcoholic KOH.

Benzene (C6H6)

  • All six C are sp2; planar hexagon, angles 120°; all C–C bonds equal = 1.397 Å (between single and double). The six unhybridized p orbitals overlap to form a delocalized π cloud above and below the ring (MO treatment).
  • Resonance: molecule represented by two or more structures (Kekulé), none of which is real; the actual hybrid is more stable. Resonance energy = difference between the calculated energy of the most stable contributing structure and the actual molecule ≈ 150 kJ/mol for benzene → extra stability.
  • Reactivity: more reactive than alkanes but less than alkenes towards addition; prefers electrophilic substitution (retains aromaticity). Does not decolourise bromine water or KMnO4.
  • Addition reactions: H2/Ni at 150–250 °C → cyclohexane; Cl2 in sunlight → benzene hexachloride (C6H6Cl6); ozonolysis → glyoxal. Methylbenzene (toluene) + H2 → methylcyclohexane.

Electrophilic substitution — mechanism

(1) Generation of electrophile E+; (2) E+ attacks π cloud → arenium ion / σ-complex (carbocation, slow step); (3) loss of H+ restores aromaticity.

ReactionReagentsElectrophileProduct
Nitrationconc. HNO3 + conc. H2SO4, 50–55 °CNO2+ (nitronium)Nitrobenzene
Sulphonationfuming H2SO4SO3Benzenesulphonic acid (reversible)
HalogenationCl2/Br2 + FeCl3/FeBr3Cl+/Br+Chlorobenzene
Friedel–Crafts alkylationRCl + anhydrous AlCl3R+Alkylbenzene (toluene)
Friedel–Crafts acylationRCOCl + AlCl3RCO+ (acylium)Ketone (acetophenone)

Methylbenzene is more reactive than benzene (CH3 activates) and gives ortho + para products; side chain: Cl2 in sunlight → benzyl chloride; KMnO4 oxidation → benzoic acid.

Orientation (directing effects)

  • Ortho/para directors (activating): –OH, –NH2, –OCH3, –CH3/alkyl. Halogens are o/p-directing but deactivating.
  • Meta directors (deactivating): –NO2, –CHO, –COOH, –COR, –SO3H, –CN, –NR3+.

Alkynes (CnH2n−2)

  • IUPAC suffix -yne (ethyne, propyne, but-1-yne, but-2-yne). sp hybridized, linear, C≡C 1.20 Å (1σ + 2π).
  • Preparation by elimination: double dehydrohalogenation of vicinal or geminal dihalides with alcoholic KOH / NaNH2 (CH2Br–CH2Br → CH≡CH); also CaC2 + 2H2O → C2H2 + Ca(OH)2.
  • Acidity: terminal alkyne H is weakly acidic because sp carbon has 50% s-character (more electronegative). Reacts with Na/NaNH2 → sodium acetylide; ammoniacal AgNO3 → white silver acetylide; ammoniacal Cu2Cl2 → red copper acetylide (distinguishes terminal alkynes from alkenes and internal alkynes). Acidity: ethyne > ethene > ethane.
  • Hydrogenation: H2/Ni or Pt → alkene → alkane; Lindlar's catalyst stops at cis-alkene.
  • Hydrohalogenation: HX adds twice (Markovnikov) → geminal dihalide (CH≡CH + 2HBr → CH3CHBr2).
  • Hydration: dil. H2SO4 + HgSO4 at 80 °C → enol → ethanal (acetaldehyde) from ethyne; other alkynes give ketones (propyne → acetone).

Substitution vs addition

Substitution: one atom/group replaces another; saturated and aromatic compounds (alkanes — free radical; benzene — electrophilic). Addition: atoms add across a multiple bond with no loss; unsaturated compounds (alkenes, alkynes — electrophilic; carbonyls — nucleophilic).

PMDC learning outcomes for this unit
  • Alkanes, alkenes, benzene, alkynes: 14.1 Describe the nomenclature of alkanes.
  • Alkanes, alkenes, benzene, alkynes: 14.2 Define free radical initiation, propagation and termination.
  • Alkanes, alkenes, benzene, alkynes: 14.3 Describe the mechanism of the free radical substitution in alkanes exemplified by methane and ethane.
  • Alkanes, alkenes, benzene, alkynes: 14.4 Explain the IUPAC nomenclature of alkenes.
  • Alkanes, alkenes, benzene, alkynes: 14.5 Explain the shapes of the ethene molecule in terms of sigma and pi C–C bonds.
  • Alkanes, alkenes, benzene, alkynes: 14.6 Describe the structure and reactivity of alkenes as exemplified by ethene.
  • Alkanes, alkenes, benzene, alkynes: 14.7 Explain dehydration of alcohols and dehydrohalogenation of RX for the preparation of ethene
  • Alkanes, alkenes, benzene, alkynes: 14.8 Explain the shape of benzene molecule (molecular orbital treatment).
  • Alkanes, alkenes, benzene, alkynes: 14.9 Define resonance, resonance energy and relative stability.
  • Alkanes, alkenes, benzene, alkynes: 14.10 Compare the reactivity of benzene with alkanes and alkenes.
  • Alkanes, alkenes, benzene, alkynes: 14.11 Define addition reactions of benzene and methylbenzene.
  • Alkanes, alkenes, benzene, alkynes: 14.12 Describe the mechanism of electrophilic substitution in benzene.
  • Alkanes, alkenes, benzene, alkynes: 14.13 Discuss chemistry of benzene and methylbenzene by nitration, sulphonation, halogenation, Friedel-Crafts alkylation and acylation.
  • Alkanes, alkenes, benzene, alkynes: 14.14 Apply the knowledge of positions of substituents in the electrophilic substitution of benzene.
  • Alkanes, alkenes, benzene, alkynes: 14.15 Use the IUPAC naming system of alkynes.
  • Alkanes, alkenes, benzene, alkynes: 14.16 Describe the preparation of alkynes using elimination reactions.
  • Alkanes, alkenes, benzene, alkynes: 14.17 Describe the acidity of alkynes
  • Alkanes, alkenes, benzene, alkynes: 14.18 Discuss chemistry of alkynes by hydrogenation, hydrohalogenation and hydration.
  • Alkanes, alkenes, benzene, alkynes: 14.19 Describe and differentiate between substitution and addition reactions.

Chemistry of Hydrocarbons MCQs with answers

Practise and track your score →
Q1
The first step of free-radical chlorination of methane is:
ATermination
BInitiation — homolysis of Cl₂
CHeterolysis of CH₄
DPropagation
Show answer
Answer: B (Initiation — homolysis of Cl₂). UV light splits Cl2 homolytically into two Cl• radicals.
Q2
Which step forms CH₃Cl and regenerates Cl•?
ATermination
BPropagation
CRearrangement
DInitiation
Show answer
Answer: B (Propagation). •CH3 + Cl2 → CH3Cl + Cl• is a chain-propagation step.
Q3
The bond angle and hybridization of carbon in ethene are:
A120°, sp²
B90°, dsp²
C180°, sp
D109.5°, sp³
Show answer
Answer: A (120°, sp²). Ethene carbons are sp² hybridized with ≈ 120° angles.
Q4
Ethene is prepared from ethanol using conc. H₂SO₄ at:
A170 °C
B25 °C
C300 °C
D140 °C
Show answer
Answer: A (170 °C). At 170 °C intramolecular dehydration gives ethene; at 140 °C (excess alcohol) diethyl ether forms.
Q5
Dehydrohalogenation of ethyl bromide to ethene is carried out with:
AAlcoholic KOH
BDilute HCl
CZn/HCl
DAqueous KOH
Show answer
Answer: A (Alcoholic KOH). Alcoholic KOH favours elimination; aqueous KOH favours substitution.
Q6
All C–C bond lengths in benzene are equal (1.397 Å) because of:
AResonance / delocalization
BHydrogen bonding
CIsomerism
Dsp³ hybridization
Show answer
Answer: A (Resonance / delocalization). Delocalized π electrons make all bonds equivalent.
Q7
The electrophile in nitration of benzene is:
AHNO₃
BNO₃⁻
CNO₂⁻
DNO₂⁺
Show answer
Answer: D (NO₂⁺). Conc. H2SO4 protonates HNO3 to generate the nitronium ion NO2⁺.
Q8
The catalyst used in Friedel–Crafts alkylation is:
APt
BAnhydrous AlCl₃
CFeCl₃ only in water
DNi
Show answer
Answer: B (Anhydrous AlCl₃). Anhydrous AlCl3 generates the carbocation electrophile.
Q9
Which group is a meta director?
A–OH
B–CH₃
C–Cl
D–NO₂
Show answer
Answer: D (–NO₂). –NO2 withdraws electrons and directs incoming electrophiles to meta.
Q10
Oxidation of methylbenzene (toluene) with KMnO₄ gives:
ABenzyl alcohol
BBenzaldehyde
CBenzoic acid
DPhenol
Show answer
Answer: C (Benzoic acid). The side chain is oxidized completely to –COOH.
Q11
Terminal alkynes are acidic because the sp-hybridized carbon has:
ANo s-character
B25% s-character
C33% s-character
D50% s-character
Show answer
Answer: D (50% s-character). More s-character makes carbon more electronegative, stabilising the acetylide ion.
Q12
Hydration of ethyne with dil. H₂SO₄ and HgSO₄ gives:
AEthanal (acetaldehyde)
BAcetone
CEthanoic acid
DEthanol
Show answer
Answer: A (Ethanal (acetaldehyde)). Vinyl alcohol (enol) forms first and tautomerizes to ethanal.
Q13
A white precipitate with ammoniacal AgNO₃ is given by:
AEthene
B2-Butyne
CEthyne
DEthane
Show answer
Answer: C (Ethyne). Terminal alkynes form insoluble silver acetylide.
Q14
Benzene undergoes addition with Cl₂ in sunlight to form:
ABenzyl chloride
BChlorobenzene
CBenzene hexachloride
DDichlorobenzene
Show answer
Answer: C (Benzene hexachloride). Free-radical addition of 3 Cl2 gives C6H6Cl6 (BHC).