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Physics · Unit 9

Current Electricity: MDCAT Notes and MCQs

Current

  • I = Q/t, ampere (1 A = 1 C s−1). Steady current: constant rate of flow of charge (same magnitude and direction with time). Conventional current flows from + to − (opposite to electrons).
  • Drift velocity of electrons is very small (≈ 10−3 m s−1) but the signal travels near light speed.

Ohm's law

Current through a conductor is directly proportional to the potential difference across its ends, provided temperature and physical conditions remain constant: V = IR. Ohmic conductors give a straight-line I–V graph; filament lamps, diodes, thermistors are non-ohmic.

Resistivity

  • R = ρL/A; resistivity ρ (Ω m) is a property of the material. Conductance G = 1/R (siemens); conductivity σ = 1/ρ.
  • Temperature dependence: Rt = R0(1 + αΔT), ρt = ρ0(1 + αΔT). α = temperature coefficient of resistivity (K−1).
  • Metals: α positive — resistance increases with temperature (more lattice vibrations). Semiconductors (Si, Ge), carbon, insulators: α negative. Alloys (manganin, constantan, nichrome): very small α.

EMF & internal resistance

  • EMF (E): energy supplied per unit charge by the source (volt). Every real source has internal resistance r.
  • Terminal voltage V = E − Ir. V < E when current flows; V = E on open circuit (I = 0). Current I = E/(R + r). Short circuit (R = 0): I = E/r — large current, heating.
  • Consequence: as load current increases, terminal voltage drops ("lost volts" Ir).

Maximum power transfer

Power to external load P = I²R = E²R/(R + r)². It is maximum when R = r (load equals internal resistance): Pmax = E²/4r. Efficiency at this point is only 50%.

PMDC learning outcomes for this unit
  • Current, resistance, emf: 9.1 Describe the concept of steady current.
  • Current, resistance, emf: 9.2 State Ohm's law.
  • Current, resistance, emf: 9.3 Define resistivity and explain its dependence upon temperature.
  • Current, resistance, emf: 9.4 Explain the internal resistance of sources and its consequences for external circuits.
  • Current, resistance, emf: 9.5 Describe the conditions for maximum power transfer.

Current Electricity MCQs with answers

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Q1
A charge of 60 C passes through a conductor in 2 minutes. The current is:
A120 A
B0.5 A
C30 A
D2 A
Show answer
Answer: B (0.5 A). I = Q/t = 60/120 = 0.5 A.
Q2
Ohm's law is valid only if:
AVoltage is AC
BTemperature remains constant
CConductor is a semiconductor
DCurrent is large
Show answer
Answer: B (Temperature remains constant). Physical conditions, especially temperature, must remain constant.
Q3
The resistance of a wire is R. If its length is doubled keeping area same, the resistance becomes:
AR
BR/2
C2R
D4R
Show answer
Answer: C (2R). R = ρL/A ∝ L.
Q4
A wire is stretched to double its length (volume constant). Its new resistance is:
AR/4
BR/2
C4R
D2R
Show answer
Answer: C (4R). L doubles and A halves → R = ρL/A becomes 4R.
Q5
For semiconductors, the temperature coefficient of resistivity is:
ANegative
BInfinite
CZero
DPositive
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Answer: A (Negative). Resistance of semiconductors decreases with rise in temperature.
Q6
The terminal voltage of a cell of emf E and internal resistance r delivering current I is:
AE + Ir
BE − Ir
CE
DIr
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Answer: B (E − Ir). Part of the emf is lost across the internal resistance.
Q7
Maximum power is delivered to an external resistance R when:
AR = r
BR = 0
CR → ∞
DR = 2r
Show answer
Answer: A (R = r). Maximum power transfer theorem: R = r.
Q8
Maximum power delivered by a source of emf E and internal resistance r is:
AE/4r
BE²/r
CE²/4r
DE²/2r
Show answer
Answer: C (E²/4r). With R = r, I = E/2r, P = I²r = E²/4r.